Hi,

I am new to var arg concept in c. I ve tried one small code which adds 5 elements using var args.


#include <stdio.h>
#include <stdarg.h>
int main()
{
int no = 5, i = 0;
int n[25], sum = 0, ret;
printf ("Enter five numbers: \n";
for (i = 0; i < 5; i++)
{
scanf ("%d", &n);
}
add (no, &sum, n[0], n[1], n[2], n[3], n[4]); /* line no. 12 */
printf ("In main \n";
printf ("Sum of five numbers is : %d\n", sum);
return 0;
}

int add (int no, int *sum, int a, int b, ...)
{ /* line no. 19*/
va_list ap;
int arg[no], i = 2;
arg[0] = a;
arg[1] = b;
va_start (ap, b);
while(i < no)
{
arg = va_arg (ap, int );
i++;
}
va_end (ap);
for (i = 0; i < no; i++)
{
sum = sum + arg;
}
printf ("Sum of %d numbers is : %d\n", no, sum);
return 0;
}


While compiling this code, I am getting error as follows.
var-args.c:19: error: conflicting types for âaddâ
var-args.c:19: note: a parameter list with an ellipsis canât match an empty parameter name list declaration
var-args.c:12: error: previous implicit declaration of âaddâ was here


Can anybody help me with fixing this bug??


Regards,
Sakthi.

Would it be possible to number in the lines, bit confusing like this

from line 19 { hasn't been closed

line 12 probably needs an int argument

from line 19 it is

{

{

}

{

}

} think maybe that is not correct in c

nah, im useless hee

Oh dear, doing my typing here, studying all that code

For line 19, specially line 27, you are using int, in the coding